(3k)^(3/2)=729

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Solution for (3k)^(3/2)=729 equation: 


D( k )

3*k < 0

3*k < 0

3*k < 0

3*k+0 < 0 // - 0

3*k < 0 // : 3

k < 0/3

k < 0

k in <0:+oo)

(3*k)^(3/2) = 729 // - 729

(3*k)^(3/2)-729 = 0

3^(3/2)*k^(3/2) = 729 // : 3^(3/2)

k^(3/2) = 729/(3^(3/2))

k^(3/2) = 729/(3^(3/2)) // ^ 2

k^3 = 19683 // ^ 1/3

k = 27

k = 27

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